121. Best Time to Buy and Sell Stock
Input: [7, 1, 5, 3, 6, 4]
Output: 5
max. difference = 6-1 = 5 (not 7-1 = 6, as selling price needs to be larger than buying price)Input: [7, 6, 4, 3, 1]
Output: 0
In this case, no transaction is done, i.e. max profit = 0.class Solution {
public:
int maxProfit(vector<int>& prices) {
int low = INT_MAX;
int max_profit = 0;
for (int p: prices){
if(p <= low) low = p;
else max_profit = p - low > max_profit? p - low: max_profit;
}
return max_profit;
}
};Last updated
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